Pieter Jelle Visser

VU University of Amsterdam - Amsterdam / Netherlands

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AD Scientific Index ID: 4703635

Vrije Universiteit Amsterdam

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	SCORES	RANKINGS
	SCORES	In VU University of Amsterdam (1,640)	In Netherlands (27,492)	In Europe (782,464)	World (2,395,197)
H Index (Total)	88	#37	#417 ^{Top 3%}	#4,762 ^{Top 3%}	#14,132 ^{Top 3%}
H Index (Last 6 Years)	69	#22	#205 ^{Top 3%}	#2,577 ^{Top 3%}	#???
H Index Last 6 years / Total Ratio	78%
i10 Index (Total)	286	#32	#410 ^{Top 3%}	#5,168 ^{Top 3%}	#???
i10 Index (Last 6 Years)	252	#25	#255 ^{Top 3%}	#3,016 ^{Top 3%}	#???
i10 Index Last 6 years / Total Ratio	88%
Citation (Total)	51,155	#21	#222 ^{Top 3%}	#3,089 ^{Top 3%}	#???
Citation (Last 6 Years)	26,732	#15	#205 ^{Top 3%}	#2,774 ^{Top 3%}	#???
Citation Last 6 years / Total Ratio	52%
Others * Click for your subject rankings Alzheimer aging mild cognitive impairment \|		-	-	-	-

* Nov 21, 2024 | According to Total H Index | BETA VERSION Notice: Please note that the subject field rankings for the world, region, country, and university are in the Beta Version due to the exclusion of profiles classified under 'Others' (873.864 scientists whose branches have not been determined or updated). These rankings will adjust as profiles are updated. Top %3 Indicator: The 'Top 3%' label indicates that a scientist ranks within the top 3% of all scientists in the AD Scientific Index for their specific subject field at the institutional, country, or world level. Reporting Inappropriate Profiles: To report inappropriate, inaccurate, or unethical profiles, including deceased scientists or profiles that require deletion, please contact [email protected]. In line with our Data Privacy Policy, if you wish to have your personal information removed, please email [email protected]. We will delete your data within 5 business days. Free Updates: To update your university or institution name, please email [email protected] with your AD Scientific Index ID and supporting documentation. Join our list to unlock premium membership benefits – click here.

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